However, if mod(numel(I), imsize) = 0, then your error might be that you want imsize number of rows, and a number of columns that makes this possible. If mod(numel(I), imsize) ~= 0 then your imsize is definitely incorrect. When converting MATLAB code it might be necessary to first reshape a matrix to a. find() on a matrix returns them, whereas NumPy’s find behaves differently. Linear indices are common in MATLAB programs, e.g. So reshape(A, 2,, 3) will become a 2xNx3 matrix, where, for a matrix with 24 elements, N will be 4. RESHAPE and LINEAR INDEXING: MATLAB always allows multi-dimensional arrays to be accessed using scalar or linear indices, NumPy does not. Now, if you know you want N rows, but don't know exactly how many columns you have, you might use the syntax, that tells MATLAB to use as many columns as necessary to make the number of elements be equal. The number of elements in the output matrix will be proportional to the product of sz1, sz2. You can't make a 1x5 vector turn into a 2x3 vector, as one element would be missing. For this to be possible, you need to have the same number of elements in the input matrix as you have in the output matrix. What reshape does is to take the matrix A, straightens it out, and gives it a new size, that's determined by the 2nd, 3rd to the Nth argument. Let's start with the syntax used in the documentation: B = reshape(A,sz1.,szN)
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